如图,CD⊥AB,BE⊥AC,垂足分别为D,E,BE,CD相交于点O,OB=OC.求证∠1=∠2.
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![如图,CD⊥AB,BE⊥AC,垂足分别为D,E,BE,CD相交于点O,OB=OC.求证∠1=∠2.](/uploads/image/z/8638860-12-0.jpg?t=%E5%A6%82%E5%9B%BE%2CCD%E2%8A%A5AB%2CBE%E2%8A%A5AC%2C%E5%9E%82%E8%B6%B3%E5%88%86%E5%88%AB%E4%B8%BAD%2CE%2CBE%2CCD%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9O%2COB%3DOC.%E6%B1%82%E8%AF%81%E2%88%A01%3D%E2%88%A02.)
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