解析几何:直线与圆设圆C方程x2+y2=r2(r>0),点M(x0,y0)是圆C内一点,O是坐标原点,则直线x0x+y0y=r2A.与圆C相离且与直线OM垂直B.与圆C相离且与直线OM不垂直C.与圆C相交且与直线OM垂直D.与圆C相交且
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/05 01:12:13
![解析几何:直线与圆设圆C方程x2+y2=r2(r>0),点M(x0,y0)是圆C内一点,O是坐标原点,则直线x0x+y0y=r2A.与圆C相离且与直线OM垂直B.与圆C相离且与直线OM不垂直C.与圆C相交且与直线OM垂直D.与圆C相交且](/uploads/image/z/8685094-22-4.jpg?t=%E8%A7%A3%E6%9E%90%E5%87%A0%E4%BD%95%EF%BC%9A%E7%9B%B4%E7%BA%BF%E4%B8%8E%E5%9C%86%E8%AE%BE%E5%9C%86C%E6%96%B9%E7%A8%8Bx2%2By2%3Dr2%EF%BC%88r%3E0%29%2C%E7%82%B9M%EF%BC%88x0%2Cy0%EF%BC%89%E6%98%AF%E5%9C%86C%E5%86%85%E4%B8%80%E7%82%B9%2CO%E6%98%AF%E5%9D%90%E6%A0%87%E5%8E%9F%E7%82%B9%2C%E5%88%99%E7%9B%B4%E7%BA%BFx0x%2By0y%3Dr2A.%E4%B8%8E%E5%9C%86C%E7%9B%B8%E7%A6%BB%E4%B8%94%E4%B8%8E%E7%9B%B4%E7%BA%BFOM%E5%9E%82%E7%9B%B4B.%E4%B8%8E%E5%9C%86C%E7%9B%B8%E7%A6%BB%E4%B8%94%E4%B8%8E%E7%9B%B4%E7%BA%BFOM%E4%B8%8D%E5%9E%82%E7%9B%B4C.%E4%B8%8E%E5%9C%86C%E7%9B%B8%E4%BA%A4%E4%B8%94%E4%B8%8E%E7%9B%B4%E7%BA%BFOM%E5%9E%82%E7%9B%B4D.%E4%B8%8E%E5%9C%86C%E7%9B%B8%E4%BA%A4%E4%B8%94)
xSMo@+>U^ֶD5[B*
$&($$Д$R!`>K]'Bǻ^f
)ɼFNpGZ7ͫ&Aho+xX%X0%8+hAE9xsC2P[Hڙ=,rNb5WR
F05bk3Pr f9*CִFO {n}Vi
(BP|jPPS]f4V-o^_Mo
$wRVpx3'@ov~><>8]