初中数学题-相似三角形如图,已知AD为△ABC的角平分线,EF为AD的垂直平分线.求证:FD²=FB·FC已知:如图,在△ABC中,∠ACB=90°,CD⊥AB于D,E是AC上一点,CF⊥BE于F.求证:EB·DF=AE·DB
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![初中数学题-相似三角形如图,已知AD为△ABC的角平分线,EF为AD的垂直平分线.求证:FD²=FB·FC已知:如图,在△ABC中,∠ACB=90°,CD⊥AB于D,E是AC上一点,CF⊥BE于F.求证:EB·DF=AE·DB](/uploads/image/z/8708046-6-6.jpg?t=%E5%88%9D%E4%B8%AD%E6%95%B0%E5%AD%A6%E9%A2%98-%E7%9B%B8%E4%BC%BC%E4%B8%89%E8%A7%92%E5%BD%A2%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5AD%E4%B8%BA%E2%96%B3ABC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%2CEF%E4%B8%BAAD%E7%9A%84%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86%E7%BA%BF.%E6%B1%82%E8%AF%81%EF%BC%9AFD%26%23178%3B%3DFB%C2%B7FC%E5%B7%B2%E7%9F%A5%EF%BC%9A%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0ACB%3D90%C2%B0%2CCD%E2%8A%A5AB%E4%BA%8ED%2CE%E6%98%AFAC%E4%B8%8A%E4%B8%80%E7%82%B9%2CCF%E2%8A%A5BE%E4%BA%8EF.%E6%B1%82%E8%AF%81%EF%BC%9AEB%C2%B7DF%3DAE%C2%B7DB)
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