在三棱柱ABC-A1B1C1中,AA1⊥平面ABC,AC=BC=AA1=2,∠ACB=90°,E为BB1的中点,∠A1DE=90°,求证:CD⊥平面A1ABB1 麻烦用坐标法做下
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/04 04:19:08
![在三棱柱ABC-A1B1C1中,AA1⊥平面ABC,AC=BC=AA1=2,∠ACB=90°,E为BB1的中点,∠A1DE=90°,求证:CD⊥平面A1ABB1 麻烦用坐标法做下](/uploads/image/z/8708058-18-8.jpg?t=%E5%9C%A8%E4%B8%89%E6%A3%B1%E6%9F%B1ABC-A1B1C1%E4%B8%AD%2CAA1%E2%8A%A5%E5%B9%B3%E9%9D%A2ABC%2CAC%3DBC%3DAA1%3D2%2C%E2%88%A0ACB%3D90%C2%B0%2CE%E4%B8%BABB1%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E2%88%A0A1DE%3D90%C2%B0%2C%E6%B1%82%E8%AF%81%EF%BC%9ACD%E2%8A%A5%E5%B9%B3%E9%9D%A2A1ABB1+%E9%BA%BB%E7%83%A6%E7%94%A8%E5%9D%90%E6%A0%87%E6%B3%95%E5%81%9A%E4%B8%8B)
xSNPUؾnNHJIR
;(-Qh
h%Q*/Ob_1'^u24USUA9ĚmrA}
Xjgtcʰ_juo[ۮ$%Jd)eXTfP%KɔJfL/Fd~̛LN,,;4ebv>J&,..&8Gr<-&Jm!&yYJlIɲt,e@S-`