设ABC为三角形的内角,且满足方程(sinB-sinA)x^2+(sinA-sinc)x+(sinC-sinB)=0有两个 相等的实根.求角B的范围
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![设ABC为三角形的内角,且满足方程(sinB-sinA)x^2+(sinA-sinc)x+(sinC-sinB)=0有两个 相等的实根.求角B的范围](/uploads/image/z/8809086-30-6.jpg?t=%E8%AE%BEABC%E4%B8%BA%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E5%86%85%E8%A7%92%2C%E4%B8%94%E6%BB%A1%E8%B6%B3%E6%96%B9%E7%A8%8B%28sinB-sinA%29x%5E2%2B%28sinA-sinc%29x%2B%28sinC-sinB%29%3D0%E6%9C%89%E4%B8%A4%E4%B8%AA+%E7%9B%B8%E7%AD%89%E7%9A%84%E5%AE%9E%E6%A0%B9.%E6%B1%82%E8%A7%92B%E7%9A%84%E8%8C%83%E5%9B%B4)
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