f(sinx)=cos2010x,f(cosx)=

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f(sinx)=cos2010x,f(cosx)=
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f(sinx)=cos2010x,f(cosx)=
f(sinx)=cos2010x,f(cosx)=

f(sinx)=cos2010x,f(cosx)=
∵f(sinx)=cos2010x
∴f(sin(π/2-x))=cos2010(π/2-x)
即f(cosx)=cos(1005π-2010x)=cos(π-2010x)=-cos2010x

f(sinx)=f(cos(π/2-x))=cos2010(π/2-x)=cos(1005π-2010x)=-cos2010x