已知数列an中,a1=1,a(n+1)=2an+1.设bn=an+1(1)求证:数列bn是等比数列(2)写出数列an的通项公式(3)设Cn=(n+1)/(an+1),求Cn的前n项和Sn请写出过程谢谢
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![已知数列an中,a1=1,a(n+1)=2an+1.设bn=an+1(1)求证:数列bn是等比数列(2)写出数列an的通项公式(3)设Cn=(n+1)/(an+1),求Cn的前n项和Sn请写出过程谢谢](/uploads/image/z/8910690-42-0.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97an%E4%B8%AD%2Ca1%3D1%2Ca%28n%2B1%29%3D2an%2B1.%E8%AE%BEbn%3Dan%2B1%281%29%E6%B1%82%E8%AF%81%3A%E6%95%B0%E5%88%97bn%E6%98%AF%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%282%29%E5%86%99%E5%87%BA%E6%95%B0%E5%88%97an%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%283%29%E8%AE%BECn%3D%28n%2B1%29%2F%28an%2B1%29%2C%E6%B1%82Cn%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CSn%E8%AF%B7%E5%86%99%E5%87%BA%E8%BF%87%E7%A8%8B%E8%B0%A2%E8%B0%A2)
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