设α∈(0,π/3) β∈(π/6,π/2) 且5/3sinα+5cosα=8 ,/2sinβ+/6cosβ =2 求cos(α+β )设α∈(0,π/3) β∈(π/6,π/2) 且5/3sinα+5cosα=8 ,/2sinβ+/6cosβ =2 求cos(α+β )的值且5√3sinα+5cosα=8 ,√2sinβ+√6cosβ =2看
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/18 20:28:57
x){n߹::09ߠopn䙁4bo\wnir~
:F Mf M
F
66@@@{:inY-Ox1 n96IE=}l.v>[:Kٌ|ڿgiy9e]m6v6#=ih j iZYX+ #=|B26dγ7R+0:!olDHV@P*[~qAb(
设α∈(0,π/3) β∈(π/6,π/2) 且5/3sinα+5cosα=8 ,/2sinβ+/6cosβ =2 求cos(α+β )设α∈(0,π/3) β∈(π/6,π/2) 且5/3sinα+5cosα=8 ,/2sinβ+/6cosβ =2 求cos(α+β )的值且5√3sinα+5cosα=8 ,√2sinβ+√6cosβ =2看
设α∈(0,π/3) β∈(π/6,π/2) 且5/3sinα+5cosα=8 ,/2sinβ+/6cosβ =2 求cos(α+β )
设α∈(0,π/3) β∈(π/6,π/2) 且5/3sinα+5cosα=8 ,/2sinβ+/6cosβ =2 求cos(α+β )的值
且5√3sinα+5cosα=8 ,√2sinβ+√6cosβ =2
看清楚,是根号哈,我弄错了
设α∈(0,π/3) β∈(π/6,π/2) 且5/3sinα+5cosα=8 ,/2sinβ+/6cosβ =2 求cos(α+β )设α∈(0,π/3) β∈(π/6,π/2) 且5/3sinα+5cosα=8 ,/2sinβ+/6cosβ =2 求cos(α+β )的值且5√3sinα+5cosα=8 ,√2sinβ+√6cosβ =2看
5/3sinα+5cosα=10sin(α+π/6)=8
sin(α+π/6)=0.8; cos(α+π/6)=0.6
同理2sin(β+π/3)=/2 ;
2cos(β+π/3)=-/2
sin(α+β+π/2)=-0.1*/2
cos(α+β )=-0.1*/2