已知半径为2的球面上有A.B.C.D四点,若AB=CD=2,则四面体ABCD的体积的最大值为?0000000答案是三分之四倍跟号下三,各位朋友给个思路,最好写出过程.
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![已知半径为2的球面上有A.B.C.D四点,若AB=CD=2,则四面体ABCD的体积的最大值为?0000000答案是三分之四倍跟号下三,各位朋友给个思路,最好写出过程.](/uploads/image/z/9446239-55-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%8D%8A%E5%BE%84%E4%B8%BA2%E7%9A%84%E7%90%83%E9%9D%A2%E4%B8%8A%E6%9C%89A.B.C.D%E5%9B%9B%E7%82%B9%2C%E8%8B%A5AB%3DCD%3D2%2C%E5%88%99%E5%9B%9B%E9%9D%A2%E4%BD%93ABCD%E7%9A%84%E4%BD%93%E7%A7%AF%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA%3F0000000%E7%AD%94%E6%A1%88%E6%98%AF%E4%B8%89%E5%88%86%E4%B9%8B%E5%9B%9B%E5%80%8D%E8%B7%9F%E5%8F%B7%E4%B8%8B%E4%B8%89%2C%E5%90%84%E4%BD%8D%E6%9C%8B%E5%8F%8B%E7%BB%99%E4%B8%AA%E6%80%9D%E8%B7%AF%2C%E6%9C%80%E5%A5%BD%E5%86%99%E5%87%BA%E8%BF%87%E7%A8%8B.)
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