lim(an^2/(3n+1)-n)=b a+b=?

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lim(an^2/(3n+1)-n)=b a+b=?
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lim(an^2/(3n+1)-n)=b a+b=?
lim(an^2/(3n+1)-n)=b a+b=?

lim(an^2/(3n+1)-n)=b a+b=?
你好!
lim [an²/(3n+1) - n]
= lim [an² - n(3n+1)]/(3n+1)
= lim [(a-3)n² - n] / (3n+1)
极限存在,必有a-3=0即a=3
极限为 -1/3 即 b = -1/3
故 a+b = 8/3

=0, arctanx--pai/2,x--无穷大 lim (arctan x)/x x→∞ = (&frac12;π)/∞ = 0 x趋向无穷大时 1/x是无穷小量,而arctanx是有

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什么意思