已知(2x-y-1)^2+|xy-2|=0求4x^2y-2xy^2+x^2y^2的值好的有赏!

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已知(2x-y-1)^2+|xy-2|=0求4x^2y-2xy^2+x^2y^2的值好的有赏!
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已知(2x-y-1)^2+|xy-2|=0求4x^2y-2xy^2+x^2y^2的值好的有赏!
已知(2x-y-1)^2+|xy-2|=0求4x^2y-2xy^2+x^2y^2的值
好的有赏!

已知(2x-y-1)^2+|xy-2|=0求4x^2y-2xy^2+x^2y^2的值好的有赏!
平方和绝对值都大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立.
所以两个都等于0
所以2x-y-1=0,2x-y=1
xy-2=0,xy=2
4x^2y-2xy^2+x^2y^2
=2xy(2x-y)+(xy)^2
=2*2*1+2^2
=8

2x-y-1=0 xy=2 算出x,y

(2x-y-1)^2+|xy-2|=0 2x-y-1=0 xy-2=0 2x-y=1 xy=2 4x^2y-2xy^2+x^2y^2 =xy(4x-2y+xy) =2[2(2x-y)+2] =2[2*1+2] =8

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