离散系统状态方程的解,在Matlab中如何绘出K=0到20个点的图形xk =(22*(-4/5)^n)/9 - (17*(-1/5)^n)/6 + 25/18(17*(-1/5)^n)/30 - (88*(-4/5)^n)/45 + 7/18>> k=1:1:20;>> y=xk;>> plot(k,y)Error using ==> plotConversion to double from sym is
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![离散系统状态方程的解,在Matlab中如何绘出K=0到20个点的图形xk =(22*(-4/5)^n)/9 - (17*(-1/5)^n)/6 + 25/18(17*(-1/5)^n)/30 - (88*(-4/5)^n)/45 + 7/18>> k=1:1:20;>> y=xk;>> plot(k,y)Error using ==> plotConversion to double from sym is](/uploads/image/z/9936801-9-1.jpg?t=%E7%A6%BB%E6%95%A3%E7%B3%BB%E7%BB%9F%E7%8A%B6%E6%80%81%E6%96%B9%E7%A8%8B%E7%9A%84%E8%A7%A3%2C%E5%9C%A8Matlab%E4%B8%AD%E5%A6%82%E4%BD%95%E7%BB%98%E5%87%BAK%3D0%E5%88%B020%E4%B8%AA%E7%82%B9%E7%9A%84%E5%9B%BE%E5%BD%A2xk+%3D%2822%2A%28-4%2F5%29%5En%29%2F9+-+%2817%2A%28-1%2F5%29%5En%29%2F6+%2B+25%2F18%2817%2A%28-1%2F5%29%5En%29%2F30+-+%2888%2A%28-4%2F5%29%5En%29%2F45+%2B+7%2F18%3E%3E+k%3D1%3A1%3A20%3B%3E%3E+y%3Dxk%3B%3E%3E+plot%28k%2Cy%29Error+using+%3D%3D%3E+plotConversion+to+double+from+sym+is)
离散系统状态方程的解,在Matlab中如何绘出K=0到20个点的图形xk =(22*(-4/5)^n)/9 - (17*(-1/5)^n)/6 + 25/18(17*(-1/5)^n)/30 - (88*(-4/5)^n)/45 + 7/18>> k=1:1:20;>> y=xk;>> plot(k,y)Error using ==> plotConversion to double from sym is
离散系统状态方程的解,在Matlab中如何绘出K=0到20个点的图形
xk =
(22*(-4/5)^n)/9 - (17*(-1/5)^n)/6 + 25/18
(17*(-1/5)^n)/30 - (88*(-4/5)^n)/45 + 7/18
>> k=1:1:20;
>> y=xk;
>> plot(k,y)
Error using ==> plot
Conversion to double from sym is not possible.
离散系统状态方程的解,在Matlab中如何绘出K=0到20个点的图形xk =(22*(-4/5)^n)/9 - (17*(-1/5)^n)/6 + 25/18(17*(-1/5)^n)/30 - (88*(-4/5)^n)/45 + 7/18>> k=1:1:20;>> y=xk;>> plot(k,y)Error using ==> plotConversion to double from sym is
你的n是什么,是1:1:20,吗?如果是的话,那你在xk等式的右边的计算法则中将有*和/的左边加上一点点——“.”即:“.*”和“./”这样的话就行了.
xk =
(22.*(-4/5).^n)./9 - (17.*(-1/5).^n)./6 + 25/18