点关于直线对称的坐标的求法题目:求点A(1,-1)关于直线x+y=1的对称点A'的坐标一般的解法是根据中点和斜率排出两个公式,求出A‘,即(1+x)/2+(-1+y)/2=1(1-x)/(-1-y)=1得(2,0)但有一种解法,是把x和y代
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![点关于直线对称的坐标的求法题目:求点A(1,-1)关于直线x+y=1的对称点A'的坐标一般的解法是根据中点和斜率排出两个公式,求出A‘,即(1+x)/2+(-1+y)/2=1(1-x)/(-1-y)=1得(2,0)但有一种解法,是把x和y代](/uploads/image/z/9968366-38-6.jpg?t=%E7%82%B9%E5%85%B3%E4%BA%8E%E7%9B%B4%E7%BA%BF%E5%AF%B9%E7%A7%B0%E7%9A%84%E5%9D%90%E6%A0%87%E7%9A%84%E6%B1%82%E6%B3%95%E9%A2%98%E7%9B%AE%EF%BC%9A%E6%B1%82%E7%82%B9A%281%2C-1%29%E5%85%B3%E4%BA%8E%E7%9B%B4%E7%BA%BFx%2By%3D1%E7%9A%84%E5%AF%B9%E7%A7%B0%E7%82%B9A%27%E7%9A%84%E5%9D%90%E6%A0%87%E4%B8%80%E8%88%AC%E7%9A%84%E8%A7%A3%E6%B3%95%E6%98%AF%E6%A0%B9%E6%8D%AE%E4%B8%AD%E7%82%B9%E5%92%8C%E6%96%9C%E7%8E%87%E6%8E%92%E5%87%BA%E4%B8%A4%E4%B8%AA%E5%85%AC%E5%BC%8F%2C%E6%B1%82%E5%87%BAA%E2%80%98%2C%E5%8D%B3%281%2Bx%29%2F2%2B%28-1%2By%29%2F2%3D1%281-x%29%2F%28-1-y%29%3D1%E5%BE%97%EF%BC%882%2C0%EF%BC%89%E4%BD%86%E6%9C%89%E4%B8%80%E7%A7%8D%E8%A7%A3%E6%B3%95%2C%E6%98%AF%E6%8A%8Ax%E5%92%8Cy%E4%BB%A3)
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