化简sin(π+α)cos(3π/2+α)+sin(π/2+α)cos(π+α)答案是-1 求过程

化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α) 化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α) (1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 （3/2*π 化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π) 化简sin(α-2π)+sin(-a-3π)cos(α-3π)/cos(π-α)-cos(-π-α)cos(α-4π) 化简cos(3/2π+π)sin(-π+α) 化简sin(α-3/2π)cos(α-π)-sin(α-2π)cos(α-π/2)=? 化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)= 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ [sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简 化简2sin[(π/2)+α]-cos(-π+α)/cos(3π+aα) 求值【sin(2π-α)sin(π+α)cos(-π-α)】/【sin(3π-α)-cos(π-α)】 化简:cos(2π-α)sin(-π-α)/sin(π/2+α)tan(3π-α) 化简sin(π/2+α)cos(3π-α)tan(π+α)/cos(π/2-α)cos(-α-π) 化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2} 化简：sinα-√3 cosα+2cos(α-π/3) 化简：2sinα^2cosα-sin（3/2π-α）cos2α= 求值：（tan10°-√3）×cos10°/sin50° 求证：[sin（2α+β）]/sinα- 2cos（α+β）=sinβ/cosα 化简cosθ+cos（θ+2π/3）+cos（θ+4π/3） 证明：sin（α+β）sin（α-β）=sin^2α-sin^2β