(log2(3)+log4(9)+……+log2^n(3^n))·log9(n次根号8)=
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计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号3计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号32
(log2(3)+log4(9)+……+log2^n(3^n))·log9(n次根号8)=
(log2 3+log4 27)(log3 4+log27 16)
化简:(log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根)
(log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根
(log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根
[log3(4)+log根下3(2)][log2(9)+log4(根3)]
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
求值:【log2(3)+log4(9)+log8(27)+log16(81)+log32(243)】—5log2(3/2)
log2^x=log4^9
(log2 3+log4 27)*(log3 4+log9 8)=log2的2是下标,后同
log2 2/3与log4 4/3哪个大怎么算…
(log2(5)+log4(125))×log3(2)/log根号3(5)
已知log2^3=a则log4^9=
log4分之9是否等于log2分之3
log2(16分之一)加log4 (8)等于多少
log2(x-4)=log4(15-x)+1
对数方程log2(x-1)=log4 x,如何化成log2(x-1)²?