设f(x-1)=x(x-1),则f(x)=( )参考答案f(x-1)=x(x-1)=[(x-1)+1] (x-1)这里[(x-1)+1] (x-1)这步中+1是怎么来

设f(x)满足f(1/x)=x/1-x设设f(x)满足f(1/x)=x/1-x ,则f(x+1)=? 设f(x)=1/x(x 设f(x)=1-x,(x 设f(x)=lgx,证明f(x)+f(x+1)=f[x(x+1)] 设函数f(x)满足f(x)+2f(1/x)=x,求f(x) 设f(x)= 1-x分之x 求f[(fx)]和f{f[f(x)]} 设f(x)+2f(1/x)=2x+1,则f(x)= 设2f(x)+f(1-x)=x^2,则f(x)=? 设f(x)=x(x-1)(x-2)...(x-999),则f'(0)=? 设f(x)=x(x-1)(x-2).(x-1000) 则f'(0)=?RT 设f(x)=x(x+1)(x+2).(x+100),则f '(0)= 设f(x)=x的平方+x分之x 则f(x分之1)等于 高数题：设f(x)=x.(x+1).(x+2).(x+n),则f 3Q 设函数f(x)=x/1-x,f(1/x)=设函数f(x)=x/1-x,则f(1/x)=急求回答 设f(x)=10^x+lgx,则f'(1)? 设f'(lnx)=1+x,则f(x)等于 设函数f(x)满足f(x)+2f(1/x)=2x+1,则f(x)= 设f(x)满足3f(x)+2f(1/x)=4x,则f(x)=＿＿.