设函数f(x)=x平方+1,g(x)=f[f(x)]先把 g(x) 的形式具体写出来 g(x) = f[f(x)] = [f(x)]^2 + 1 = (x^2 +1)^2 + 1 = x^4 + 2x^2 + 2 G(x) = g(x)-cf(x) = x^4 + 2x^2 + 2 - c(x^2 + 1) = x^4 + (2-c)x^2 + 2-c 配方 G(x) = x^4 + 2*[(2-c)/2] x^2 + [(2-

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