设x,y,z∈R,2x+2y+z+8=0,则(x-1)2+(y+2)2+(z-3)2最小值是关于柯西不等式的.
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/20 23:45:08
x){n_NNգ
mJ*m[35*t
55*@Tѳ9
O7?ml{6}Zl7v6t{zڿYSbPlu-h
jťFk`l]vlTFB%lhBtBdj@-ֵ@0p?젡eDcX-
mmCGK,6͇ld. y
设x,y,z∈R,2x+2y+z+8=0,则(x-1)^2+(y+2)^2+(z-3)^2最小值
设x,y,z∈R+,且3^x=4^y=6^z.求证1/z-1/x=1/2y.
设x,y,z∈R,2x+2y+z+8=0,则(x-1)2+(y+2)2+(z-3)2最小值是关于柯西不等式的.
设x,y,z∈,R求证:x²+xz+z²+3y(X+y+z)≥0
高一数学必修五基本不等式设x,y,z∈R+,且满足x-2y+3z=0,则y²/xz的最小值
设X+Y+Z=0求X^3+X^2Z-XYZ+Y^2Z+Y^3的值
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
若x,y,z∈R,且x+y+z=xyz,求证:(y+z)/x+(z+x)/y+(x+y)/z≥2(1/x+1/y+1/z)^2
若x,y,z∈R+,且x+y+z=xyz,求证:(y+z)/x+(z+x)/y+(x+y)/z>2(1/x+1/y+1/z)
已知x,y,z∈ R,x+2y=z+6,x-y=3-2z,求x^2+y^2+z^2的最小值.
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值
一道初2数学题目 运用设K解决 速度已知(y+z)/x=(z+x)/y=(x+y)/z (x+y+z≠0) 求(x+y-z)/(x+y+z)的值
设z≠0 x、y、z 满足4x-7y-5z=0 2x-y-z=0 求x:y
设z≠0,x、y、z满足4x-7y-5z=0、2x-y-z=0,求x:y
设函数z=z(x,y)由方程e^(-xy)-2z+e^z=0确定,求z/x,z/y
设Z=X+Y,其中X,Y满足X+2Y>=0,X-Y
设f(x,y,z)=e^x*y*z^2,其中z=z(x,y)是由x+y=z+x*e^(z-x-y)确定的隐函数,则f'x(0,1,1)=