dy/dx-2y/(x+1)=(x+1)^2急求、、请好心人发下过程.阿门求解微分方程。。

dy/dx,y=(1+x+x^2)e^x dy/dx=1+1/(x-y) dy/dx=1-cos(y-x) dy/dx=x(1-y) dy/dx = 1/x-y dy/dx=(e^x+x)(1+y^2)通解 dy/dx=x(1+y^2)/y通解 y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy (x^2)dy+（y^2)dx=dx-dy x=sint+1 y=2cos3t dy/dx 求解微分方程dy/dx+x/2y=1/2 dy/dx=1+x+y^2+xy^2 微分方程解法dy/dx-x/(2y)=1/2 设y=√(x^2-1)求dy/dx dy/dx=1/(x+y)^2的通解为 dy／dx=（x-y）^2+1通解 dy/dx=1/(x–y^2)的通解 x^2+xy+y^3=1,求dy/dx