x=sint+1 y=2cos3t dy/dx

x=sint+1 y=2cos3t dy/dx x=sint,y=cos2t,求dy/dx不好意思..忘了x=1/2 此参数方程为什么这么解x=2(t-cost)y=2(1-sint)求dy/dx.答案是dy/dx = -cost/(1+sint)为什么dx= 2(1+sint)dt为什么dy= -2cost 设x=t^2+cost,y=1-sint,求dy/dx 设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2 sint-tcost/4t^3 和 sint-tcost/4t^2 哪个对?设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2sint-tcost/4t^3 和 sint-tcost/4t^2 哪个对? 已知﹛x=7(t-sint),y=7(1-cost),则dy/dx= 此参数方程怎么解?x=2(t-cost)y=2(1-sint)求dy/dx.为什么是这样解呢?dx= 2(1+sint)dtdy= -2costdy/dx = -cost/(1+sint) 求x=e^t*cost,y=e^t*sint所确定的函数的二阶导数,求讲解x't=(e^t)(sint+cost)y't=(e^t)(cost-sint)x''t=(e^t)(sint+cost+cost-sint)=2(e^t)costy''t=(e^t)(cost-sint-sint+cost)=-(e^t)sintdy/dx=(cost-sint)/(sint+cost)d^2 y/d(x^2)=d(dy/dx)/dx=(y''x 高数:摆线x=a(t-sint),y=a(1-cost)(0《=t《2π)确定隐函数y=y(x),求dy/dx 高数求导（dy/dx）习题设由下列方程确定y是x的函数,求dy/dx(1)cos(x^2 +y)=x求下列参数方程所确定的函数y=f(x)的导数dy/dx(1)x=(e^t)sint,y=(e^t)cost.(1)-[1+2xsin(x^2 +y)]/[sin(x^2 +y)](2)cost-sint/sint+cost 求导数 x=3t²+2t+3 y=e^y*sint+t 求 dy/dx x=3t²+2t+3 y=(e的y次幂)·sint + 1 ,求在t=0时 dy/dx=? x=3t²+2t+3 y=(e的y次幂)·sint + 1 ,求在t=0时 dy/dx=? 参数方程：x=5(t-sint) y=5(1-cost) 求d^2y/dx^2 dy/dx我会求 已知{x=sint^2 y=（2t+5）^2 求dy/dx已知{x=sint^2y=（2t+5）^2 求dy/dx x=2t^2 +1 y= sint 求dy/dx是多少?x 等于2t的平方再加1, 求导：已知x=2sint-t^2,y=3cost+t^3,求dy/dx 参数方程求导 x=a(t-sint) y=a(1-cost) 求dy/dx 各种不会 求解决