如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE急急急！！！！！！！

已知:如图所示,AB=AC,BD=CE,AD=AE,求证∠BAC=∠DAE 如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE 如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE急急急！！！！！！！ 已知AB=AC,AD=AE,∠BAC=∠DAE.求证：BD=CE. 如图,已知AB=AC,∠ABD=∠ACE,∠BAC=∠DAE求证：BD=CE... 已知:如图∠DAE=∠BAC,AB=AC,∠B=∠C求证:AD=AE 如图,已知AB=AC,AD=AE,BD=CE.试说明：∠BAC=∠DAE 已知:如图,AB=AC,AD=AE,BD=CE,求证:∠BAC=∠DAE 已知,如图6-7,AD=AE,AB=AC,∠DAE=∠BAC求证:BD=CE 如图,已知AB=AC,AD=AE,∠BAC=∠DAE求证BD=CE 如图所示:三角形ABC的两边AB、AC的垂直平分线分别交BC于D、E两点,且∠BAC+∠DAE=150°,求∠的度数.求∠BAC的度数 如图,已知∠BAC=∠DAE ,∠ABD=∠ACE ,BD=CE 求证:AB=AC,AD=AE 如图,已知∠BAC=∠DAE,∠1=∠2,BD=CE.求证:AB=AC,AD=AE 如图,已知∠BAC=∠DAE,∠1=∠2,BD=CE.求证:AB=AC,AD=AE 已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,说明AB=AC,AD=AE, 如图,已知∠BAC=∠DAE,AB=AC,AD=AE,你能说明BD=CE,∠ABD=∠ACE么?T0T) 已知,如图AB=AC,AD=AE,∠BAC=∠DAE求证：（1）△ABD≌△ACE (2)∠ADB=∠AEC 如图,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,那么AB与AC,AD与AE有什么数量关系?