如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE
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如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE
如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE
如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE
∵∠BAC=∠DAE
∠BAD=∠BAC-∠DAC,∠CAE=∠DAE-∠DAC
∴∠BAD=∠CAE
又∵∠ABD=∠ACE ,BD=CE
∴△BAD≌△CAE(AAS)
∴AB=AC,AD=AE
∵∠BAC=∠DAE
∠BAD=∠BAC-∠DAC,∠CAE=∠DAE-∠DAC
∴∠BAD=∠CAE
又∵∠ABD=∠ACE ,BD=CE
∴△BAD≌△CAE(AAS)
∴AB=AC,AD=AE
已知:如图所示,AB=AC,BD=CE,AD=AE,求证∠BAC=∠DAE
如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE
如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE急急急!!!!!!!
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