超难数学几何题 如图,△ABC为等腰直角三角形,∠BAC=90度,D为AC的中点,AE⊥BD于E,求证∠BAE=∠FDC file:///C:/Documents%20and%20Settings/Administrator/Local%20Settings/Temporary%20Internet%20Files/Content.IE5/YPJSX0N2/2010050910
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 00:39:27
xRMo@+v7!F#wc!riMؖm\jQ%$*P BH_9Wpz#rֹNxЏ'Ѥ=_ghf?LGhܤg< aDAX.8!v^DA_