∫(0,PI/2) sin^4 (x) dx

∫(0,PI/2) sin^4 (x) dx 函数COSX-SINX >0我这么做：根号2 SIN(PI/4-x)>0 sin (pi/4 -x)>0pi-2kpi 函数COSX-SINX >0我这么做：根号2 SIN(PI/4-x)>0 sin (pi/4 -x)>0pi-2kpi ∫sqrt(4-4*sin^2(x)) dx 范围[2pi/3,0] ∫sin^7(2x)dx在0到pi/4的定积分 已知cos(x)=sqrt(10)/10,x属于(0,pi/2),求sin(pi/4+2x)的值 matlab提示Error:Incomplete or misformed expression or statement.x=0:2*pi:100;s=20*(4*x/pi-(1/(2*pi))*sin(8*pi*x/pi);plot(x,s);求指导. Matlab u(x,t)=sin(5*pi*x)cos(5*pi*t)+2sin(7*pi*x)cos(7*pi*t) 其中0 化简sin(2x-pi)sin[x+(3/2)pi]/cos[x+(5/2)pi][1-sin(pi+x)] |sin(x-y)|dxdy积分区域 0<x<y<2pi答案是2pi 但是我怎么算出来是4pi呢? 2(sin^4 x + cos^4 x) =1 [ - pi ≤ x ≤ pi ] f(2x)=sin (x+3*pi/4)+cos (x-pi/2), f(x)h(x)=√2/2sin(x+pi/4)cos(x+5pi/4) =-√2/2sin(x+pi/4)cos(x+pi/4)√2/2sin(x+pi/4)cos(x+5pi/4) =-√2/2sin(x+pi/4)cos(x+pi/4)这个是怎么化出来的? 已知sin(x+pi/6)=1/4,求sin（5pi/6-x)+sin^2(pi/3-x)的值 根号2/4sin(pi/4-x)+pi/4cos(pi/4-x),我明天还要交啊，555555555555555555555555 sin(x/2) = 2/3 [0≤x≤pi/2] cosx?tanx?sin(x/4) sin(x/2) = 2/3 [0≤x≤pi/2] 怎样求：（要程序!1） cosx?tanx?sin(x/4) 定积分问题:范围是0到pi/2 ∫sin ^2x / sin x+cos x dx If sin(x) = 4/5,pi/2 < x < pi,find the value of sin(2x)