lg(|A|+|B|)/2≥lg(|A|+lg|B|)/2(AB≠0)
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lg(a b) = lg a lg
lg(|A|+|B|)/2≥lg(|A|+lg|B|)/2(AB≠0)
求证:lg(|A|+|B|)/2≥lg(|A|+lg|B|)/2(AB≠0)
求证:lg(|A|+|B|)/2≥(lg|A|+lg|B|)/2 (AB≠0)
-lg(a+b)=lg(a-b).
lg(a+b)/2+lg(b+c)/2+lg(a+c)/2>lga+lgb+lgc
求证lg(a+b)/2+lg(b+c)/2+lg(c+a)/2>lga+lgb+lgc
求证:lg (|A|+|B|)/2>=(lg|A|+lg|B|)/2
求证lg1/2(/A/+/B/)≥1/2(lg/A/+lg/B/)
lg 2=a lg 3=b.lg 2=a lg 3=b 表示 log 5
lg[a^lga)+lg(b^lgb)+lg(c^lgc)为什么等于lg²a+lg²b+lg²c
已知log14 7=a,log14 5=b,求log35 28(用a,b表示)log 14 7 = lg 7 / lg 14 log 14 5 = lg 5 / lg 14 A = lg 7 / lg 14 = lg 7 / (lg 7 + lg 2) B = lg 5 / lg 14 = (1 - lg2) / (lg 7 + lg 2) 通过以上两式可得:lg 7 = A / (1 - A + B) lg 2 = (1 - A) / (
Lg(a)+Lg(b)=2Lg(a-2b).求Log(4)a/b的值.
lg(a-b)=?lg(a+b)=?
lg(a+b)与lg(a-b)的关系
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证:lg(a+b/2)+lg(b+c/2)+lg(c+a/2)>lga+lgb+lgc,abc不全相等
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