已知三角形ABC,P为BC边上一定点,过P做一直线,使其等分三角形ABC的面积1,若点P恰为BC的中点,做直线AP即可2,若P不是BC的中点,则取BC的中点D,联结AP,过点D做DE平行AP交AC于E,作直线PE,直线PE即为所求
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![已知三角形ABC,P为BC边上一定点,过P做一直线,使其等分三角形ABC的面积1,若点P恰为BC的中点,做直线AP即可2,若P不是BC的中点,则取BC的中点D,联结AP,过点D做DE平行AP交AC于E,作直线PE,直线PE即为所求](/uploads/image/z/10150107-51-7.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%89%E8%A7%92%E5%BD%A2ABC%2CP%E4%B8%BABC%E8%BE%B9%E4%B8%8A%E4%B8%80%E5%AE%9A%E7%82%B9%2C%E8%BF%87P%E5%81%9A%E4%B8%80%E7%9B%B4%E7%BA%BF%2C%E4%BD%BF%E5%85%B6%E7%AD%89%E5%88%86%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E9%9D%A2%E7%A7%AF1%2C%E8%8B%A5%E7%82%B9P%E6%81%B0%E4%B8%BABC%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E5%81%9A%E7%9B%B4%E7%BA%BFAP%E5%8D%B3%E5%8F%AF2%2C%E8%8B%A5P%E4%B8%8D%E6%98%AFBC%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E5%88%99%E5%8F%96BC%E7%9A%84%E4%B8%AD%E7%82%B9D%2C%E8%81%94%E7%BB%93AP%2C%E8%BF%87%E7%82%B9D%E5%81%9ADE%E5%B9%B3%E8%A1%8CAP%E4%BA%A4AC%E4%BA%8EE%2C%E4%BD%9C%E7%9B%B4%E7%BA%BFPE%2C%E7%9B%B4%E7%BA%BFPE%E5%8D%B3%E4%B8%BA%E6%89%80%E6%B1%82)
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