已知x>y,且xy=1,求证:(x2+y2/x-y)≥2根号2要具体过程和最后答案~~~~

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已知x>y,且xy=1,求证:(x2+y2/x-y)≥2根号2要具体过程和最后答案~~~~
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已知x>y,且xy=1,求证:(x2+y2/x-y)≥2根号2要具体过程和最后答案~~~~
已知x>y,且xy=1,求证:(x2+y2/x-y)≥2根号2
要具体过程和最后答案~~~~

已知x>y,且xy=1,求证:(x2+y2/x-y)≥2根号2要具体过程和最后答案~~~~
左边=[(x-y)^2+2xy]/(x-y)
=(x-y)+2/(x-y)>=2根号二------均值不等式,其中x-y>0