设z=(x+2y)e^xy,求dz

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设z=(x+2y)e^xy,求dz
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设z=(x+2y)e^xy,求dz
设z=(x+2y)e^xy,求dz

设z=(x+2y)e^xy,求dz
dZ = эZ&#47;эx *dx + эz&#47;эy*dy              = y*e^(xy)*cos(xy)*dx + e^(xy)*[-ysin(xy)]*dx                 + x*e^(xy)*cos(xy)*dy + e^(xy)*[-xsin(xy)*dy         dZ|(01) = 1*e^0*cos0*dx - e^0*y*sin0*dx +0*e^0*cos0*dy - e^0*0*sin0*dy                      = dx