设z=(x+2y)e^xy,求dz
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/20 12:41:03
x){n_FQfj\EγM)U6IE8dlJz~\ y7{M},ӕ*PTT+D"= ]{rxH6{g=řy0"
]S5()Q*60*!
A$
6UHX4Vbh4@HBdĔ
<;P
>~5
设z=(x+2y)e^xy,求dz
设z=(x+2y)e^xy,求dz
设z=(x+2y)e^xy,求dz
dZ = эZ&#47;эx *dx + эz&#47;эy*dy = y*e^(xy)*cos(xy)*dx + e^(xy)*[-ysin(xy)]*dx + x*e^(xy)*cos(xy)*dy + e^(xy)*[-xsin(xy)*dy dZ|(01) = 1*e^0*cos0*dx - e^0*y*sin0*dx +0*e^0*cos0*dy - e^0*0*sin0*dy = dx
设z=(x+2y)e^xy,求dz
设z=f(2x+3y,e^xy),求dz
设Z=f(x^2 +y,2xy),求dz/dx和dz/dy
设z=z(x,y)是由方程e^(-xy)+2z-e^z=2确定 求dz|(x=2,y=-1/2)
设z=z(x,y)是由方程e^(-xy)+2z-e^z=2确定 求dz|(x=2,y=-1/2)
设z=(x+y)^xy,求dz
设z=arctan(xy),y=e^x ,求dz/dx .
二元函数 设z=(x平方-y平方)e的xy次方,求dz
设z=f(xy,e^x+y),求dz高数计算题,坐等大侠
设z=z(x,y)由e^(-xy)-2z+e^z=0所确定的二元函数 求dz
设方程xz+yz+xy=e的定函数z=z(x,y),求dz
设z=u^2cosv^2,u=x+y,v=xy,求dz/dx,dz/dy.高数题
设函数z=f(x,y)由方程e^z=xyz+cos(xy)求dz/dx ,dz/dy.求详解
设f(x,y)具有一阶连续偏导数,z=xf(x^y,e^xy),求dz
设z=arctan(xy)+2x^2+y^2,求dz
设z=xy+sint,而x=e^t,y=cost,求导数dz/dt求详细解答
设z=x^y,求dz
全导数:设z=arctan(xy),而y=e*x次方,求dz/dx设z=arctan(xy),而y=e*x次方,求dz/dx,