关于反函数的二阶导数问题若y=f(x)三阶可导 设g(y)=x则可以证明g’(y)=1/y' (不用证)根据以上条件求g''(y)我的思路是g''(y)=(1/y')'=(y'^(-1))'=(y')'(-1)(y')^(-2)=-y''/y'^2 请问错在哪里看不出错的就不要
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![关于反函数的二阶导数问题若y=f(x)三阶可导 设g(y)=x则可以证明g’(y)=1/y' (不用证)根据以上条件求g''(y)我的思路是g''(y)=(1/y')'=(y'^(-1))'=(y')'(-1)(y')^(-2)=-y''/y'^2 请问错在哪里看不出错的就不要](/uploads/image/z/1042731-27-1.jpg?t=%E5%85%B3%E4%BA%8E%E5%8F%8D%E5%87%BD%E6%95%B0%E7%9A%84%E4%BA%8C%E9%98%B6%E5%AF%BC%E6%95%B0%E9%97%AE%E9%A2%98%E8%8B%A5y%3Df%28x%29%E4%B8%89%E9%98%B6%E5%8F%AF%E5%AF%BC+%E8%AE%BEg%28y%29%3Dx%E5%88%99%E5%8F%AF%E4%BB%A5%E8%AF%81%E6%98%8Eg%E2%80%99%28y%29%3D1%2Fy%27+%EF%BC%88%E4%B8%8D%E7%94%A8%E8%AF%81%EF%BC%89%E6%A0%B9%E6%8D%AE%E4%BB%A5%E4%B8%8A%E6%9D%A1%E4%BB%B6%E6%B1%82g%27%27%28y%29%E6%88%91%E7%9A%84%E6%80%9D%E8%B7%AF%E6%98%AFg%27%27%28y%29%3D%281%2Fy%27%29%27%3D%28y%27%5E%28-1%29%29%27%3D%28y%27%29%27%28-1%29%28y%27%29%5E%28-2%29%3D-y%27%27%2Fy%27%5E2+%E8%AF%B7%E9%97%AE%E9%94%99%E5%9C%A8%E5%93%AA%E9%87%8C%E7%9C%8B%E4%B8%8D%E5%87%BA%E9%94%99%E7%9A%84%E5%B0%B1%E4%B8%8D%E8%A6%81)
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