sinx-cosx=根号2/2,则cosx+sinx的值为?

tanx=根号2,则(2cos^2x/2-sinx-1)/(sinx+cosx)= 根号2cos(x-π/2)怎么=sinx+cosx 证明：sinx-cosx=-根号2cos(x+派/4) cosx+根号3sinx=2cos(x-π/3) sinx-cosx=(根号3)/3,则cos(π/2-2x)=? 已知cosx-sinx=3根号2/5,则5sin2x/cos(x+π/4)= 证明2(cosx-sinx)/(1+sinx+cosx)=cosx/(1+sinx)-sinx/(1+cos) 根号3sinx-cosx=?-1/2sinx-cosx=?-sinx-根号3cosx=? cosx-sinx=根号2sinx,求证tanx=cosx-sinx/cosx+sinx谢谢了, 根号2cosx-根号6sinx=```````` tanx=根号2,(cosx-sinx)/(cosx+sinx)=? 已知sinx+cosx=根号2 求 sinx乘以cosx cosx-2cos(cosxcos60+sinxsin60)怎么变成-根号3sinx sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x 答案:设1小于等于COSx-SINx小于等于根号2,则函数y=1-cos x+sin x+sinx cosx的值域为? 设(2cosx-sinx)(sinx+cosx-3)=0则cos^2x= 证明(1+secx+tanx)/(1+secx-tanx)=(1+sinx)/cosx左边=（cosx/cosx+1/cosx+sinx/cosx)/（cosx/cosx+1/cosx-sinx/cosx)=(cosx+1+sinx)/(cosx+1-sinx)=(cosx+1+sinx)^2/[(cosx+1+sinx)(cosx+1-sinx)]=(cos²x+sin²x+2*sinx*cosx+2*cosx+2*sinx+1)/(cos² tana=根号2,求[2cos^2(x/2)-sinx-1]/(sinx+cosx)的值cosx=2cos(x/2)^2-1为什么？