已知f''(x)在[0,1]上连续,f'(1)=0,且f(1)-f(0)=2,则∫(0,1)xf''(x)dx=求高数大神!详细过程

来源:学生作业帮助网 编辑:作业帮 时间:2024/09/01 04:35:24
已知f''(x)在[0,1]上连续,f'(1)=0,且f(1)-f(0)=2,则∫(0,1)xf''(x)dx=求高数大神!详细过程
x){}K5*4YmcdG׋^aikdǔ4 K7M@HiG5j5+ ZS*lmlzzƳ.Y|<=b6IET l^ l9 -`Q[pJH"Xf׀%ta*ҐktLD@7X~qAb x

已知f''(x)在[0,1]上连续,f'(1)=0,且f(1)-f(0)=2,则∫(0,1)xf''(x)dx=求高数大神!详细过程
已知f''(x)在[0,1]上连续,f'(1)=0,且f(1)-f(0)=2,则∫(0,1)xf''(x)dx=
求高数大神!详细过程

已知f''(x)在[0,1]上连续,f'(1)=0,且f(1)-f(0)=2,则∫(0,1)xf''(x)dx=求高数大神!详细过程
∫(0,1)xf''(x)dx
=∫(0,1)xdf'(x)
=xf'(x)|(0,1)-∫(0,1)f'(x)dx
=f'(1)-0-f(x)|(0,1)
=0-[f(1)-f(0)]
=-2