lim(x趋向于无穷) 1/x^a(积分上限x^2 积分下限0)√(1+t^4)dt 存在且不为零,则常数a=?极限值是多少
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![lim(x趋向于无穷) 1/x^a(积分上限x^2 积分下限0)√(1+t^4)dt 存在且不为零,则常数a=?极限值是多少](/uploads/image/z/10779571-19-1.jpg?t=lim%28x%E8%B6%8B%E5%90%91%E4%BA%8E%E6%97%A0%E7%A9%B7%29+1%2Fx%5Ea%28%E7%A7%AF%E5%88%86%E4%B8%8A%E9%99%90x%5E2+%E7%A7%AF%E5%88%86%E4%B8%8B%E9%99%900%29%E2%88%9A%281%2Bt%5E4%29dt+%E5%AD%98%E5%9C%A8%E4%B8%94%E4%B8%8D%E4%B8%BA%E9%9B%B6%2C%E5%88%99%E5%B8%B8%E6%95%B0a%3D%3F%E6%9E%81%E9%99%90%E5%80%BC%E6%98%AF%E5%A4%9A%E5%B0%91)
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lim(x趋向于无穷) 1/x^a(积分上限x^2 积分下限0)√(1+t^4)dt 存在且不为零,则常数a=?极限值是多少
lim(x趋向于无穷) 1/x^a(积分上限x^2 积分下限0)√(1+t^4)dt 存在且不为零,则常数a=?极限值是多少
lim(x趋向于无穷) 1/x^a(积分上限x^2 积分下限0)√(1+t^4)dt 存在且不为零,则常数a=?极限值是多少
把x^a 放到分母上
http://chart.googleapis.com/chart?cht=tx&chl=\lim_{x\to\infty}\frac{1}{x^a\int_{0}^{x^2}\sqrt{1%2Bt^4}\,dt}
然后求导
显然要求有极限存在,则-a-1=4 则a=-5
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lim(x趋向于无穷) 1/x^a(积分上限x^2 积分下限0)√(1+t^4)dt 存在且不为零,则常数a=?极限值是多少
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