1,{2sin50+cos10(1+√3tan10)}/√(1+cos10)=?2,1/sin10-√3/sin80=?(度我不会打)

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/05 14:42:16
1,{2sin50+cos10(1+√3tan10)}/√(1+cos10)=?2,1/sin10-√3/sin80=?(度我不会打)
xMN0RUԪ%q]=؎MBb.X v=g@J\{`ͧse%`kGaHǻՆXQ=}Xe36R8z:C6~}VvsX}oשZ'4O\{͝q:mۜREu[@ai]/cQC1]~׼#ihQPn6 M FhN P.pa&ABK1(I,X_+bbJ1x(s4(tNd"jڽw&

1,{2sin50+cos10(1+√3tan10)}/√(1+cos10)=?2,1/sin10-√3/sin80=?(度我不会打)
1,{2sin50+cos10(1+√3tan10)}/√(1+cos10)=?
2,1/sin10-√3/sin80=?(度我不会打)

1,{2sin50+cos10(1+√3tan10)}/√(1+cos10)=?2,1/sin10-√3/sin80=?(度我不会打)