在△ABC中,∠A,∠B都是锐角,且sinA=1/2,cosB=(根号3)/2,则△ABC是( )三角形(要解释,)最好是有个图
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![在△ABC中,∠A,∠B都是锐角,且sinA=1/2,cosB=(根号3)/2,则△ABC是( )三角形(要解释,)最好是有个图](/uploads/image/z/1127208-48-8.jpg?t=%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0A%2C%E2%88%A0B%E9%83%BD%E6%98%AF%E9%94%90%E8%A7%92%2C%E4%B8%94sinA%3D1%2F2%2CcosB%3D%EF%BC%88%E6%A0%B9%E5%8F%B73%EF%BC%89%2F2%2C%E5%88%99%E2%96%B3ABC%E6%98%AF%EF%BC%88+%EF%BC%89%E4%B8%89%E8%A7%92%E5%BD%A2%EF%BC%88%E8%A6%81%E8%A7%A3%E9%87%8A%2C%EF%BC%89%E6%9C%80%E5%A5%BD%E6%98%AF%E6%9C%89%E4%B8%AA%E5%9B%BE)
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