sin50(1+根号3倍的tan10)-cos20,再整体除以cos80*根号下(1-cos20)求这个值是多少,关于三角函数的
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![sin50(1+根号3倍的tan10)-cos20,再整体除以cos80*根号下(1-cos20)求这个值是多少,关于三角函数的](/uploads/image/z/1129594-58-4.jpg?t=sin50%EF%BC%881%2B%E6%A0%B9%E5%8F%B73%E5%80%8D%E7%9A%84tan10%EF%BC%89-cos20%2C%E5%86%8D%E6%95%B4%E4%BD%93%E9%99%A4%E4%BB%A5cos80%2A%E6%A0%B9%E5%8F%B7%E4%B8%8B%EF%BC%881-cos20%EF%BC%89%E6%B1%82%E8%BF%99%E4%B8%AA%E5%80%BC%E6%98%AF%E5%A4%9A%E5%B0%91%2C%E5%85%B3%E4%BA%8E%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0%E7%9A%84)
sin50(1+根号3倍的tan10)-cos20,再整体除以cos80*根号下(1-cos20)求这个值是多少,关于三角函数的
sin50(1+根号3倍的tan10)-cos20,再整体除以cos80*根号下(1-cos20)求这个值是多少,关于三角函数的
sin50(1+根号3倍的tan10)-cos20,再整体除以cos80*根号下(1-cos20)求这个值是多少,关于三角函数的
(sin50°(1+√3*tan10°)-cos20°)/(cos80°*√(1-cos20°))
=(sin50°(1+√3*sin10°/cos10°)-cos20°)/(cos80°*√(1-cos20°))
=(sin50°((cos10°+√3*sin10°)/cos10°)-cos20°)/(cos80°*√(2(sin10°)^2))
=(sin50°((1/2)cos10°+(√3/2)*sin10°)/((1/2)*cos10°)-cos20°)/(cos80°*√(2(sin10°)^2))
=(sin50°(sin30°*cos10°+cos30°*sin10°)/(1/2)*cos10°-cos20°)/((√2)cos80°*sin10°)
=(sin50°*sin40°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=(sin50°*cos50°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)sin100°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)sin80°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)cos10/(1/2)*cos10°-cos20°)/((√2)sin10°sin10°)
=(1-cos20°)/((√2)sin10°sin10°)
=2(sin10°)^2/(√2)(sin10°)^2
=2/√2
=√2