如图,AB⊥AC,NC⊥AC,AB=AC,M为AC中点,AN⊥BM交BC于D,BC平分∠ACN 求证:△ABM≌△CAN ∠AMB=∠CMD如图,AB⊥AC,NC⊥AC,AB=AC,M为AC中点,AN⊥BM交BC于D,BC平分∠ACN求证:△ABM≌△CAN∠AMB=∠CMD
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![如图,AB⊥AC,NC⊥AC,AB=AC,M为AC中点,AN⊥BM交BC于D,BC平分∠ACN 求证:△ABM≌△CAN ∠AMB=∠CMD如图,AB⊥AC,NC⊥AC,AB=AC,M为AC中点,AN⊥BM交BC于D,BC平分∠ACN求证:△ABM≌△CAN∠AMB=∠CMD](/uploads/image/z/11315958-6-8.jpg?t=%E5%A6%82%E5%9B%BE%2CAB%E2%8A%A5AC%2CNC%E2%8A%A5AC%2CAB%3DAC%2CM%E4%B8%BAAC%E4%B8%AD%E7%82%B9%2CAN%E2%8A%A5BM%E4%BA%A4BC%E4%BA%8ED%2CBC%E5%B9%B3%E5%88%86%E2%88%A0ACN+%E6%B1%82%E8%AF%81%EF%BC%9A%E2%96%B3ABM%E2%89%8C%E2%96%B3CAN+%E2%88%A0AMB%3D%E2%88%A0CMD%E5%A6%82%E5%9B%BE%2CAB%E2%8A%A5AC%2CNC%E2%8A%A5AC%2CAB%3DAC%2CM%E4%B8%BAAC%E4%B8%AD%E7%82%B9%2CAN%E2%8A%A5BM%E4%BA%A4BC%E4%BA%8ED%2CBC%E5%B9%B3%E5%88%86%E2%88%A0ACN%E6%B1%82%E8%AF%81%EF%BC%9A%E2%96%B3ABM%E2%89%8C%E2%96%B3CAN%E2%88%A0AMB%3D%E2%88%A0CMD)
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