y^2-2xy+b*b=0,求dy/dx
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y^2-2xy+b*b=0,求dy/dx
y^2-2xy+b*b=0,求dy/dx
y^2-2xy+b*b=0,求dy/dx
y²-2xy+b²=0
两边同时对x求导得:
2yy '-2(y+xy ')=0
yy '-y-xy '=0
得 y '=y/(y-x)
即dy/dx=y/(y-x)
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