点P为正方形ABCD边BC上任一点,BG⊥AP于点G,在AP的延长线上取点E,使AG=GE,连接BE、CE.做∠CBE的平分线交AE于N点,连接DN,求证DN⊥BN
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![点P为正方形ABCD边BC上任一点,BG⊥AP于点G,在AP的延长线上取点E,使AG=GE,连接BE、CE.做∠CBE的平分线交AE于N点,连接DN,求证DN⊥BN](/uploads/image/z/11675844-36-4.jpg?t=%E7%82%B9P%E4%B8%BA%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E8%BE%B9BC%E4%B8%8A%E4%BB%BB%E4%B8%80%E7%82%B9%2CBG%E2%8A%A5AP%E4%BA%8E%E7%82%B9G%2C%E5%9C%A8AP%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8A%E5%8F%96%E7%82%B9E%2C%E4%BD%BFAG%3DGE%2C%E8%BF%9E%E6%8E%A5BE%E3%80%81CE.%E5%81%9A%E2%88%A0CBE%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4AE%E4%BA%8EN%E7%82%B9%2C%E8%BF%9E%E6%8E%A5DN%2C%E6%B1%82%E8%AF%81DN%E2%8A%A5BN)
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