判断(x^2+3sinx-sin兀/4)' =2x+3cosx-cos兀/4
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判断(x^2+3sinx-sin兀/4)' =2x+3cosx-cos兀/4
判断(x^2+3sinx-sin兀/4)' =2x+3cosx-cos兀/4
判断(x^2+3sinx-sin兀/4)' =2x+3cosx-cos兀/4
错
sinπ/4是常数,导数为0
所以应该等于2x+3cosx
不对呀,=2x+3cosx
sin兀/4为常数,导数的0
错,应该是2x+3cosx,sin兀/4是常数,常数的导数是0
(x^2+3sinx-sin兀/4)' =2x+3cosx
sin兀/4是常数,常数的导数是0
判断(x^2+3sinx-sin兀/4)' =2x+3cosx-cos兀/4
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