判断下列函数的奇偶性 (1),y=lg(sinx+√(1+sin²x))(2)y=(1+sinx-cosx)/(1-sinx+cosx) (3) y=√(lg cosx) (4) y=xsins+x²cos2x
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![判断下列函数的奇偶性 (1),y=lg(sinx+√(1+sin²x))(2)y=(1+sinx-cosx)/(1-sinx+cosx) (3) y=√(lg cosx) (4) y=xsins+x²cos2x](/uploads/image/z/5924483-35-3.jpg?t=%E5%88%A4%E6%96%AD%E4%B8%8B%E5%88%97%E5%87%BD%E6%95%B0%E7%9A%84%E5%A5%87%E5%81%B6%E6%80%A7+%281%29%2Cy%3Dlg%28sinx%2B%E2%88%9A%EF%BC%881%2Bsin%26%23178%3Bx%EF%BC%89%EF%BC%89%EF%BC%882%EF%BC%89y%3D%281%2Bsinx-cosx%29%2F%281-sinx%2Bcosx%29+%283%29+y%3D%E2%88%9A%28lg+cosx%29+%284%29+y%3Dxsins%2Bx%26%23178%3Bcos2x)
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