已知函数f(x)=ax^2-2x+lnx(1)若F(x)无极值点,但其导函数F’(x)有零点,求a的值.(2)f(x)有两个极值点,求a的取值范围,并证明f(X)的极小值.
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![已知函数f(x)=ax^2-2x+lnx(1)若F(x)无极值点,但其导函数F’(x)有零点,求a的值.(2)f(x)有两个极值点,求a的取值范围,并证明f(X)的极小值.](/uploads/image/z/11923434-18-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%29%3Dax%5E2-2x%2Blnx%281%29%E8%8B%A5F%28x%29%E6%97%A0%E6%9E%81%E5%80%BC%E7%82%B9%2C%E4%BD%86%E5%85%B6%E5%AF%BC%E5%87%BD%E6%95%B0F%E2%80%99%EF%BC%88x%29%E6%9C%89%E9%9B%B6%E7%82%B9%2C%E6%B1%82a%E7%9A%84%E5%80%BC.%EF%BC%882%EF%BC%89f%EF%BC%88x%EF%BC%89%E6%9C%89%E4%B8%A4%E4%B8%AA%E6%9E%81%E5%80%BC%E7%82%B9%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%2C%E5%B9%B6%E8%AF%81%E6%98%8Ef%28X%29%E7%9A%84%E6%9E%81%E5%B0%8F%E5%80%BC.)
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