dx/dy=x/y+[cos(x/y)]∧2,y(0)=1
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dx/dy=x/y+[cos(x/y)]∧2,y(0)=1
dx/dy=x/y+[cos(x/y)]∧2,y(0)=1
dx/dy=x/y+[cos(x/y)]∧2,y(0)=1
dy/dx=1-cos(y-x)
dy/dx=cos(x+y+1)
d{cos(x-y)=sin(x-y)(dx-dy)这里dx-dy是什么意思呢?
x=cos y' ,其中y'=dy/dx
dx/dy=x/y+[cos(x/y)]∧2,y(0)=1
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解这个微分方程 cos(x+y)dy=dx
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(x^2)dy+(y^2)dx=dx-dy