第1题 已知:abc≠0 a+b+c=0 证:a(1/b+1/c)+b(1/a+1/c)+c(1/b+1/c)+3=0第2题 设:abc=1 求a/(ab+a+1)+b/(bc+b+1)+c/(ca+c+1)的值
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![第1题 已知:abc≠0 a+b+c=0 证:a(1/b+1/c)+b(1/a+1/c)+c(1/b+1/c)+3=0第2题 设:abc=1 求a/(ab+a+1)+b/(bc+b+1)+c/(ca+c+1)的值](/uploads/image/z/12529569-57-9.jpg?t=%E7%AC%AC1%E9%A2%98+%E5%B7%B2%E7%9F%A5%EF%BC%9Aabc%E2%89%A00+a%2Bb%2Bc%3D0+%E8%AF%81%EF%BC%9Aa%281%2Fb%2B1%2Fc%29%2Bb%281%2Fa%2B1%2Fc%29%2Bc%281%2Fb%2B1%2Fc%29%2B3%3D0%E7%AC%AC2%E9%A2%98+%E8%AE%BE%EF%BC%9Aabc%3D1+%E6%B1%82a%2F%28ab%2Ba%2B1%29%2Bb%2F%28bc%2Bb%2B1%29%2Bc%2F%28ca%2Bc%2B1%29%E7%9A%84%E5%80%BC)
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