如图,直线AB、CD相交于点O,OE平分∠BOC,OF⊥CD,若OB将∠DOE分成2:3两部分,求∠AOF的度数.答案上说的是90°/7或45°,我算出来是45°,可是90°/7是怎么算出来的?画图:cd为水平直线,ab是随便相交于cd的
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![如图,直线AB、CD相交于点O,OE平分∠BOC,OF⊥CD,若OB将∠DOE分成2:3两部分,求∠AOF的度数.答案上说的是90°/7或45°,我算出来是45°,可是90°/7是怎么算出来的?画图:cd为水平直线,ab是随便相交于cd的](/uploads/image/z/12601903-31-3.jpg?t=%E5%A6%82%E5%9B%BE%2C%E7%9B%B4%E7%BA%BFAB%E3%80%81CD%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9O%2COE%E5%B9%B3%E5%88%86%E2%88%A0BOC%2COF%E2%8A%A5CD%2C%E8%8B%A5OB%E5%B0%86%E2%88%A0DOE%E5%88%86%E6%88%902%EF%BC%9A3%E4%B8%A4%E9%83%A8%E5%88%86%2C%E6%B1%82%E2%88%A0AOF%E7%9A%84%E5%BA%A6%E6%95%B0.%E7%AD%94%E6%A1%88%E4%B8%8A%E8%AF%B4%E7%9A%84%E6%98%AF90%C2%B0%2F7%E6%88%9645%C2%B0%2C%E6%88%91%E7%AE%97%E5%87%BA%E6%9D%A5%E6%98%AF45%C2%B0%2C%E5%8F%AF%E6%98%AF90%C2%B0%2F7%E6%98%AF%E6%80%8E%E4%B9%88%E7%AE%97%E5%87%BA%E6%9D%A5%E7%9A%84%3F%E7%94%BB%E5%9B%BE%EF%BC%9Acd%E4%B8%BA%E6%B0%B4%E5%B9%B3%E7%9B%B4%E7%BA%BF%2Cab%E6%98%AF%E9%9A%8F%E4%BE%BF%E7%9B%B8%E4%BA%A4%E4%BA%8Ecd%E7%9A%84)
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