{bn}为等差数列,bn=(2n^2-n)/(n+c),求非0常数c

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{bn}为等差数列,bn=(2n^2-n)/(n+c),求非0常数c
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{bn}为等差数列,bn=(2n^2-n)/(n+c),求非0常数c
{bn}为等差数列,bn=(2n^2-n)/(n+c),求非0常数c

{bn}为等差数列,bn=(2n^2-n)/(n+c),求非0常数c
因为(2n^2-n)=n(2n-1)=2n(n-0.5)要使bn为等差数列(n+c)必为分子的一个因式由c不等于零可知c必等于-0.5

c=0

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