方程组①x/2=y/3=z/4②x+2y+3z=80
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方程组①x/2=y/3=z/4②x+2y+3z=80
方程组①x/2=y/3=z/4②x+2y+3z=80
方程组①x/2=y/3=z/4②x+2y+3z=80
【参考答案】
x/2=y/3=z/4 ①
x+2y+3z=80 ②
由①得
x=z/2,y=(3/4)z
将x=z/2、y=(3/4)z带入②得
(z/2)+(3/2)z+3z=80
z=16
则x=8,y=12
∴原方程组的解是x=8,y=12,z=16
x=8 y=12 z=16
设x/2=y/3=z/4=k(k≠0),所以x=2k,y=3k,z=4k,将其代入第二个方程,得k=4,所以x=8,y=12,z=16
解方程组x+y/2=z+x/3=y+z/4①x+y+z=27②
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方程组①x/2=y/3=z/4②x+2y+3z=80
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