作业帮解方程：(1)sin2x=cos3x (2)sin(2x+π/3)+sin(x-π/6)=0 (3)sin(x+π/6)+cos(x+π/6)=0
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/16 02:30:07
xQ
0\%e2.
!PLDV@blXߎ i{G~qiN]Í :aLƞ 0%ѫ$udI2;jR#[șZ2up7Vʩ0A}qn~ c 94؊1 'xiÔL2&`,_u45@<' ]ӻ@(ֵuSO7
解方程：(1)sin2x=cos3x (2)sin(2x+π/3)+sin(x-π/6)=0 (3)sin(x+π/6)+cos(x+π/6)=0
解方程：(1)sin2x=cos3x (2)sin(2x+π/3)+sin(x-π/6)=0 (3)sin(x+π/6)+cos(x+π/6)=0
解方程：(1)sin2x=cos3x (2)sin(2x+π/3)+sin(x-π/6)=0 (3)sin(x+π/6)+cos(x+π/6)=0
(1)sin2x-cos3x=0
sin2x-sin(π/2-3x)=0
2sin(π/4-x/2)cos(5x/2-π/4)=0
x/2-π/4=kπ或5x/2-π/4=kπ+π/2
x=2kπ+π/2或x=2kπ/5+3π/10
(2)sin(2x+π/3)=-sin(x-π/6)=sin(π/6-x)
2x+π/3=2kπ+π/6-x
x=2kπ/3-π/18
(3)tan(x+π/6)=-1=tan(-π/4)
x+π/6=kπ-π/4
x=kπ-5π/6
证 sin2x * cos3x =(1/2) * [sin5x + sin(-x)]
1+sinX+sin2X+sin3X=cosX-cos2X+cos3X解方程.或者解 sin2X-cos2X+sinX+cosX=0上面那个太麻烦… 唉 万恶的三角函数= =
解方程：(1)sin2x=cos3x (2)sin(2x+π/3)+sin(x-π/6)=0 (3)sin(x+π/6)+cos(x+π/6)=0
cos3x.sinx=1/2(sin4x-sin2x)是怎么证明的?
求y=sin2x+cos3x的最小正周期
函数f(x)=cos3x/cosx+2sin2x的最大值
化简2sin2x*sinx+cos3x
复合函数求导1题y=sin2x+cos2x 一定要复合函数求导y=sin2x+cos3x U= V=
cosX=cos3x解三角方程
解方程；SinX+Sin2X+Sin3X = 1+CosX+Cos2X.
方程(cos2x)^2-(sin2x)^2=1的解集
解方程3(sinx-cosx-1)=sin2x
方程sin2X=(sinX)^2怎么解
解方程 sin2x/sinx=cos2x/cosx
求cosx*cos2x*cos3X=1 的所有解,
cosx^2+cos3x^2=1解三角方程
y=Cos3x+Sin2x的最小正周期是多少?怎么算?
数学求不定积分,高手请帮忙!谢谢!S(sin2x)(cos3x)dx=?希望看到解题过程.