(2+1)(2^2+1)(2^4+1)(2^8+1)要有过程!
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(2+1)(2^2+1)(2^4+1)(2^8+1)要有过程!
(2+1)(2^2+1)(2^4+1)(2^8+1)要有过程!
(2+1)(2^2+1)(2^4+1)(2^8+1)要有过程!
(2+1) (2^2 +1) (2^4 +1) (2^8 +1)
=(2^2-1) (2^2 +1) (2^4 +1) (2^8 +1)
=(2^4 -1) (2^4 +1) (2^8 +1)
=(2^8 -1) (2^8 +1)
=2^16 -1
原式=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)
=(2^4 -1) (2^4 +1) (2^8 +1)
=(2^8 -1) (2^8 +1)
=2^16 -1
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15=?
(1+1/2)(1+1/2^2)(1+1/2^4)^(1+1/2^32)
(2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
计算:(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)/(2^32)-1=?
求和:1+(1+2)+(1+2+4)+(1+2+4+6)+(1+2+4+.2^n-1)
计算:(2+1)({2}^{2}+1)({2}^{4}+1)({2}^{8}+1)...({2}^{256}+1)
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^2048+1),
(2+1)(2^2-1)(2^4+1)(2^8+1)(2^16-1)(2^32+1)(2^64+1)
(-2k-1)^2+4(-k^2+1)
(1-1/2^2)(1-1/3^2)(1-1/4^2)……(1-1/100^2)=( )
1-1/2^2)*(1-1/3^2)*(1-1/4^2)*...*(1-1/2004^2)
计算:(1+2)(1+2^2)(1+2^4)(1+2^8)(1+2^16)(1+2^32)(1+2^64)
(2+1)(2^2+1)(2^4+1)(2^8+1)要有过程!
化简(1+2^(-1/32))(1+2^(-1/16))(1+2^(-1/8))(1+2^(-1/4))(1+2^(-1/2))
1/2,1/4,
lim(1-1/2n).(1+1/2+1/4+.+1/2^n)