已知封闭曲线C由曲线C1:x=cosα+1,y=sinα α∈[-π/2,π/2]和曲线C2:x^2+y^2=2(x已知封闭曲线C由曲线C1:x=cosα+1,y=sinα α∈[-π/2,π/2]和曲线C2:x^2+y^2=2(x≤1)组成(1)以原点为极点,x轴正半轴为极轴建立极
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![已知封闭曲线C由曲线C1:x=cosα+1,y=sinα α∈[-π/2,π/2]和曲线C2:x^2+y^2=2(x已知封闭曲线C由曲线C1:x=cosα+1,y=sinα α∈[-π/2,π/2]和曲线C2:x^2+y^2=2(x≤1)组成(1)以原点为极点,x轴正半轴为极轴建立极](/uploads/image/z/14949344-56-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%B0%81%E9%97%AD%E6%9B%B2%E7%BA%BFC%E7%94%B1%E6%9B%B2%E7%BA%BFC1%3Ax%3Dcos%CE%B1%2B1%2Cy%3Dsin%CE%B1+%CE%B1%E2%88%88%5B-%CF%80%2F2%2C%CF%80%2F2%5D%E5%92%8C%E6%9B%B2%E7%BA%BFC2%3Ax%5E2%2By%5E2%3D2%28x%E5%B7%B2%E7%9F%A5%E5%B0%81%E9%97%AD%E6%9B%B2%E7%BA%BFC%E7%94%B1%E6%9B%B2%E7%BA%BFC1%EF%BC%9Ax%3Dcos%CE%B1%2B1%2Cy%3Dsin%CE%B1+%CE%B1%E2%88%88%5B-%CF%80%2F2%2C%CF%80%2F2%5D%E5%92%8C%E6%9B%B2%E7%BA%BFC2%EF%BC%9Ax%5E2%2By%5E2%3D2%28x%E2%89%A41%29%E7%BB%84%E6%88%90%EF%BC%881%EF%BC%89%E4%BB%A5%E5%8E%9F%E7%82%B9%E4%B8%BA%E6%9E%81%E7%82%B9%2Cx%E8%BD%B4%E6%AD%A3%E5%8D%8A%E8%BD%B4%E4%B8%BA%E6%9E%81%E8%BD%B4%E5%BB%BA%E7%AB%8B%E6%9E%81)
已知封闭曲线C由曲线C1:x=cosα+1,y=sinα α∈[-π/2,π/2]和曲线C2:x^2+y^2=2(x已知封闭曲线C由曲线C1:x=cosα+1,y=sinα α∈[-π/2,π/2]和曲线C2:x^2+y^2=2(x≤1)组成(1)以原点为极点,x轴正半轴为极轴建立极
已知封闭曲线C由曲线C1:x=cosα+1,y=sinα α∈[-π/2,π/2]和曲线C2:x^2+y^2=2(x
已知封闭曲线C由曲线C1:x=cosα+1,y=sinα α∈[-π/2,π/2]和曲线C2:x^2+y^2=2(x≤1)组成
(1)以原点为极点,x轴正半轴为极轴建立极坐标系,试画出曲线C的草图并写出曲线C的极坐标方程
(2)过原点的直线l:θ=π/4(ρ∈R)交曲线C于点A,B,求︱AB︱
(3)过原点的直线l交曲线C于点A,B,当︱AB︱=2+√2时,写出直线l的极坐标方程
(4)过原点的直线l交曲线C于点A,B,求︱AB︱的取值范围
已知封闭曲线C由曲线C1:x=cosα+1,y=sinα α∈[-π/2,π/2]和曲线C2:x^2+y^2=2(x已知封闭曲线C由曲线C1:x=cosα+1,y=sinα α∈[-π/2,π/2]和曲线C2:x^2+y^2=2(x≤1)组成(1)以原点为极点,x轴正半轴为极轴建立极
曲线C1:x=cosα+1,y=sinα α∈[-π/4,π/4]和曲线C2:x^2+y^2=2(x≤1)组成曲线C
1. p= 2cos θ, θ∈[-π/4,π/4) ; p=2, θ∈[π/4,7π/4)
2. 交点A(1,1), B(-1,-1), |AB| = 2√2
3. 直线l 即x 轴,极坐标方程为 θ=0 及 θ=π .
4. 【2√2,2+√2】