求y=sin(2x-π/3) +1 X∈(-π/3,2π/3)的值域,谢谢

已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 sinx=1/3,sin(x+y)=1,求sin（2y+x）=? siny=1/3,sin(x＋y)=1,求sin(2x＋y) (cosx)^2-(cosy)^2=1/3求sin(x+y)*sin(x-y). y =(cos^2) x - sin (3^x),求y' Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y) sin^2x+cos^2y=1/2 求3sin^2x+sin^2y的最值 求函数y=sin(x+1/3兀)sin(x+1/2兀)的周期 已知Sin x+Sin y=1/2,Cos x+Cos y=根号3/3,求S求Sin(x-y)/2 已知x∈(0,π),求函数y=√3sinθ/(1+3sin^2θ)的最大值 sin(x+y)cosx+cos(x+y)sinx=1/3 x∈(3π/2,2π) 求cos(2x+π/4) 求导数 y=sin^2(2x+π/3) y=sin(x+π/3)+2定义域怎么求? y=sin(2x-π/3) x∈(π/2,π)求值域 y=sin(2x+π/6),x∈[π/4,3π/4]求值域 求函数的值域y=sin(2x+π/3),x∈(-π/6,π) 求y=sin(2x+π/6)x∈(0,π/3)的值域 求函数y=3sin(2x+π/4),x∈R的周期